Question

Find the equation of the line that passes through the points (6,7) and (-12,10)

Answer 1

To find the equation of the line that passes through the points (6,7) and (-12,10), we need to first find the slope of the line. We can use the slope formula:

m = (y2 - y1) / (x2 - x1)

where (x1,y1) = (6,7) and (x2,y2) = (-12,10).

Substituting these values, we get:

m = (10 - 7) / (-12 - 6) = 3 / (-18) = -1/6

Now that we have the slope, we can use either of the two points to find the y-intercept b. Let's use the point (6,7):

y = mx + b

7 = (-1/6)(6) + b

7 = -1 + b

b = 8

Therefore, the equation of the line that passes through the points (6,7) and (-12,10) is:

y = (-1/6)x + 8

Explanation:

Answer 2

first find slope
slope=m=(10-7)/(-12-6)
m=-3/18
m=-1/6

equation
y-10=-1/6(x+12)
6y-60=-x-12
x+6y=48