Question

Hi, can you help me answer this question please, thank you!

Answer 1

The sample size given in the question is

`n=37`

The mean weight is

`\bar{x}=50`

The standard deviation is

`\sigma=8.4`

The margin of error is calculated using the formula below

`\text{MOE = Z-score(90\% C.I)}*\frac{\sigma}{\sqrt[]{n}}`

Using the Z-score table, the Z-score for the 90% confidence interval is

`=1.645`

By substituting the values in the formula above, we will have

`\begin{gathered} \text{MOE = Z-score(90\% C.I)}*\frac{\sigma}{\sqrt[]{n}} \\ \text{Margin of error(MOE)} \\ =1.645*\frac{8.4}{\sqrt[]{37}} \\ =\frac{13.818}{\sqrt[]{37}} \\ =\pm2.272\text{ounces} \end{gathered}`

Hence,

The final answer is = ±2.272 ounces