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Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is the vacuum cleaner?
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Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is the vacuum cleaner?

User Wilco
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Power efficiency is defined as the ratio of the output power divided by the input power:
Efficiency= out/in • 100%
So, (120 - 45)J / 120J • 100% = 62.5%
User Subb
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