Question

A school bus with the football team left Jefferson HighSchool and drove at an average speed of 48 mph. A schoolbus with the cheerleading squad left 2 hours later and wasable to catch up to the football team after 6 hours. Whatwas the speed of the bus carrying the school's cheerleadingsquad?

Answer 1

Given data

A school bus with the football team from Jefferson High School drove at an average speed of 48mph

Another school bus with the cheerleading squad left 2 hours later and caught with the football team after 6 hours.

Required

To find the speed of the bus carrying the Cheerleading squad.

Step 1

Determine the distance the bus carrying the football team had travelled in the first 2 hours

Speed is given as

`\begin{gathered} \text{speed =}(dis\tan ce)/(time) \\ \text{where sp}eed\text{ = 48mph} \\ \text{time = 2 hours} \\ \text{distance = sp}eed\text{ x time} \\ \text{distance = 48 x 2 =96miles} \end{gathered}`

Step 2

Determine of the distance covered by the bus with the football team in the next 6 hours and find the total distance in 8 hours

`\begin{gathered} \text{Distance = sp}eed\text{ }*\text{ time} \\ where \\ \text{speed = 48mph} \\ \text{time = 6 hours} \\ \text{Distance = 48 }*\text{ 6 = 288 miles} \end{gathered}`

The total distance in 8 hours covered by the bus = 288 + 96 = 384miles

Step 3

Determine the speed of the bus carrying the Cheerleaders

The total distance to be covered by the Cheerleaders is 384 miles

The total time of their journey to catch with the bus carrying the Football team is 6hours

Hence the speed of the bus required is given as

`\begin{gathered} \text{Speed = }(dis\tan ce)/(time) \\ \text{speed = }(384)/(6) \\ \text{speed = 64mph} \end{gathered}`

Therefore, the speed of the bus carrying the school's Cheerleaders squad is 64mph