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Given g(x) = x square -7x + 1over4 show that the least possible value of g(x) is -12

1 Answer

5 votes

Answer:


-(45)/(16)

Explanation:


g(x)=(x^(2) -7x+1)/(4)

Take the derivate of g:


g'(x)=(x-7)/(4)

Find x that:

g'(x)=0

solving:


(2x-7)/(4)=0\\x=(7)/(2)

This x give the least possible value that are g(7/2):


g((7)/(2)) =-(45)/(16)

User Ayrnieu
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