Question

Given g(x) = x square -7x + 1over4 show that the least possible value of g(x) is -12

Answer 1

`-(45)/(16)`

Explanation:

`g(x)=(x^(2) -7x+1)/(4)`

Take the derivate of g:

`g'(x)=(x-7)/(4)`

Find x that:

g'(x)=0

solving:

`(2x-7)/(4)=0\\x=(7)/(2)`

This x give the least possible value that are g(7/2):

`g((7)/(2)) =-(45)/(16)`