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Given an exponential function for compounding interest, A(x) = P(1.02)x, what is the rate of change?
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Given an exponential function for compounding interest, A(x) = P(1.02)x, what is the rate of change?

User Agentem
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1 Answer

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A(x) = P(1.02)^x
A(x) = P(1 + 0.02)^x
A(x) = P(1 + r)^x

Therefore rate of change = 0.02 = 2%
User MRu
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