Question

A 60-kg skier starts at the top of a 10-meter high slope. At the bottom, she is traveling 10m/s. How much energy does she lose to friction?

PLZZZZZZZZZZ HELP FAST!!!

Answer 1

The answer is 2880... I took the test

Explanation:

Answer 2

Use conversion:

`1 joule = 1 kg m^2/s^2`

As per the given statement:

Mass of the skier(m) = 60 kg

height of the slope(h) = 10m/s

Speed(v) = 10m/s

By conservation of Energy states the law of conservation of energy states that the total energy of an isolated system remains constant.

`P.E - K.E + E = 0`

P.E(Potential Energy) = mgh

K.E(Kinetic Energy)=
`(1)/(2)mv^2`

E represents the energy lose due to friction.

then;

`mgh -(1)/(2)mv^2 + E = 0`

Substitute the given values;

Use
`g = 9.8 m/s^2`

then;

`(60)(9.8)(10) -(1)/(2)(60)(10)^2 + E = 0`

Simplify:

`5880-3000+E = 0`

`2880+E =0`

or

`E = -2880 kgm^2/s^2`

Therefore, the energy does she lose to friction is 2880 joule