Question

If Lanny spins the spinner below 70 times, how many times can he expect is to land on a number divisible by 3? *

Answer 1

From 1 to 10, there are 3, 6, and 9 are divisible by 3

Then we have 3 choices out of 10 numbers

Since the probability = an event/outcomes

Since the event is 3

Since the outcomes are 10, then

`P((no)/(3))=(3)/(10)`

This is the probability for spinning the spinner one time

But we need to spin it 70 times

We will multiply 3/10 by itself 70 times, which means make it to the power of 70

`P((no)/(3))=((3)/(10))^(70)`

The answer is (3/10)^70 OR (0.3)^70