Mary estimates the weight of her cat to be 10 pounds.the actual weight of the cat is 13.75 pounds.find the percent error.

DoubleDouble asked Dec 5, 2023

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DoubleDouble asked Dec 5, 2023

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17 votes

The percentage error is the ratio of the difference between the two readings and the actual

Error = 13.75 - 10

= 3.75

Percent error = 3.75/13.75

= 27.27%

DAiMor answered Dec 9, 2023

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