Question

B) Use the quadratic formula to find the roots of each quadratic function.

Answer 1

`\begin{gathered} \text{the roots of a polynomial of the form} \\ ax^2+bx+c=0 \\ \text{are} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \\ So,\text{ a=3, b = -4, c = 2} \end{gathered}`
`\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(3)(2)}}{2(3)} \\ x=\frac{4\pm\sqrt[]{16-24}}{6} \\ x=\frac{4\pm\sqrt[]{-8}}{6} \\ \\ so\text{ the roots are} \\ \\ x=\frac{4+\sqrt[]{8}i}{6} \\ \text{and} \\ x=\frac{4-\sqrt[]{8}i}{6} \end{gathered}`