Question

Write an equation in point-slope form of the line having the given slope that contains the given point. then graph the line

(dont think u can graph so its okay)

Answer 1

The line of the equation in the point-slope form of the line passing through the point (3, -1) and having slope 1/2 will be:

`y +1 = (1)/(2) (x-3)`

Please check the attached graph.

Explanation:

Given

• The slope m = 1/2

• The point (3, -1)

Point slope form:

`y-y_1=m\left(x-x_1\right)`

where

• m is the slope of the line

• (x₁, y₁) is the point

In our case:

m = 1/2

The point (x₁, y₁) = (3, -1)

substituting the values m = 1/2 and the point (x₁, y₁) = (3, -1) in the point-slope form of the line equation

`y-y_1=m\left(x-x_1\right)`

`y - (-1) = (1)/(2) (x-3)`

`y +1 = (1)/(2) (x-3)`

Thus, the line of the equation in the point-slope form of the line passing through the point (3, -1) and having slope 1/2 will be:

`y +1 = (1)/(2) (x-3)`

Please check the attached graph.