8in 8in 8in area of irregular figures

Petr Averyanov asked Jun 2, 2023

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Petr Averyanov asked Jun 2, 2023

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21 votes

Given data:

The given figure.

The expression for the area is,

$\begin{gathered} A=(8\text{ in)(8 in)+}(1)/(2)(8\text{ in)( 8 in)} \\ =96in^2 \end{gathered}$

Thus, the area of the given ffigure is 96 square-inches.

Nikartix answered Jun 9, 2023

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