Question

Manipulate the following equation to solve for t: s=1/2 at^2

Answer 1

S=1/2at^2
2s=at^2
2s/a=t^2
T=sqaure root of 2s/a

Answer 2

Step-by-step explanation:

It is given by :

`s=(1)/(2)at^2`..... (1)

Where

s = distance covered

a = acceleration of an object

t = time taken

We need to manipulate given equation to find the value of t. On cross multiplication to both side of equation (1) we get:

`2s=at^2`

Dividing both side of above equation by a we get :

`t^2=(2s)/(a)`

Taking square root of above equation we get :

`t=\sqrt{(2s)/(a)}`

So, the value of t is,
`t=\sqrt{(2s)/(a)}`. Hence, this is the required solution.