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How to find oxidation number of ReO4^-?

User Manuchehr
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1 Answer

16 votes
16 votes

The oxidation number of O is usually -2 and in this case it is.

Our ion is ReO₄⁻. It has a total charge of -1. The charge of the four atoms of O is -8. With this information we can write an equation. X will represent the oxidation state of Re.

Total charge = Oxidation state of Re + 4 * Oxidation state of O

- 1 = x + 4 * (-2)

- 1 = x - 8

-1 + 8 = x

x = +7

So the oxidation state of Re is +7.

User Veiset
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