Question

Determine the perimeter of this shape. Use 3.14 for pi. the numbers are 12m and 15 m

Answer 1

We are asked to find the perimeter of the figure. To do that we will add the perimeters of the semi-circle and the rectangle.

To determine the perimeter of the semi-circle we will use the following formula:

`P_{c\text{ }}=(\pi D)/(2)`

The diameter is 12 m. Replacing in the formula we get:

`P_c=(\pi(12m))/(2)`

Solving the operations:

`P_c=(3.14(12))/(2)=6.28m`

Now we will find the perimeter of the rectangle by adding the length of all of its sides:

`P_R=15m+12m+15m=42m`

Now, the perimeter of the figure is the sum of the perimeters we found:

`\begin{gathered} P=P_c+P_R \\ \end{gathered}`

Replacing:

`P=6.28m+42m=48.28m`

Therefore, the perimeter of the figure is 48.28m