Question

Please help me with this question I have a test next week and I really have to study this is 11th grade algebra 2

Answer 1

(a)

(b) P(x < 4) = 0.29

(c) P(x= 6) = 0.17

(d) P(x ≥ 5) = 0.34

Explanation:

The probability in each case would be the specific amount divided by the total amount, therefore, we calculate the total amount and the probability in each case, like this:

`\begin{gathered} 5+10+2+9+33+12+15+3+1\:=\:90 \\ \\ P(0)=(5)/(90)=0.06 \\ \\ P(1)=(10)/(90)=0.11 \\ \\ P(2)=(2)/(90)=0.02 \\ \\ P(3)=(9)/(90)=0.1 \\ \\ P(4)=(33)/(90)=0.37 \\ \\ P(5)=(12)/(90)=0.13 \\ \\ P(6)=(15)/(90)=0.17 \\ \\ P(7)=(3)/(90)=0.03 \\ \\ P(8)=(1)/(90)=0.01 \end{gathered}`

Therefore, the table would look like this:

With this we calculate the probability in each case:

`\begin{gathered} P\left(x<4\right)=P\left(x=0\right)+P\left(x=1\right)+P\left(x=2\right)+P\left(x=3\right)=0.06+0.11+0.02+0.10=0.29 \\ \\ P(x=6)=0.17 \\ \\ P(x\ge5)=P\left(x=5\right)+P\left(x=6\right)+P\left(x=7\right)+P\left(x=8\right)=0.13+0.17+0.03+0.01=0.34 \end{gathered}`