Question

What is the sequence that has a recursive formula A(n)= A(n-1)+4 where A(1)=3

Answer 1

`(3,7,11,15,\ldots)`

1) Considering that, let's find each term:

`\begin{gathered} a_1=3 \\ a_n=a_(n-1)+4 \\ a_2=a_1+4\Rightarrow a_2=3+4=7 \\ a_3=a_2+4\Rightarrow a_3=7+4\text{ =11} \\ a_4=11+4\text{ }\Rightarrow a_4=15 \end{gathered}`

2) So the sequence is

`(3,7,11,15,\ldots)`

As each term, from the 2nd one is 4 units more that's why we can make it using a recursive formula