Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point 2x+9y=-30;(-8,0)

Answer 1

y=(-30-2x)/9 the slop is -2/9 because perpendicular to the given line so the new slop is 9/2
y=9/2x+b
0=9/2*-8+b
0=-36+b
b=36
y=9/2x+36 is the answer

Answer 2

`y=(9)/(2)x+36`

Explanation:

The given equation is 2x+9y=-30.

Subtracting 2x both sides :

9y=-2x-30

Dividing both sides by 9 we have:

`y=(-2)/(9)x -(10)/(3)`

This equation is of the form y=mx+b where the slope m=
`(-2)/(9)`

Slope of a perpendicular line =
`(9)/(2)`

The perpendicular line passes through the point (-8,0)

The equation of the perpendicular line is :
`y-0=(9)/(2) (x+8)`

Or
`y=(9)/(2)x+36`