Question

Hello I need help completing this practice math problem, I will include a picture. Thank you so much!

Answer 1

To answer this question we will set and solve a system of equations.

Let k be the number of orders that Kala served on Monday, a be the number of orders that Abdul served, and j be the number of orders that Joe served.

Since they served a total of 71 orders, Kala served 5 fewer orders than Abdul, and Joe served 2 times as many orders as Abdul, then we can set the following system of equations:

`\begin{gathered} k+a+j=71, \\ k=a-5, \\ j=2a\text{.} \end{gathered}`

Substituting the second and third equation in the first one we get:

`a-5+a+2a=71.`

Adding like terms we get:

`4a-5=71.`

Adding 5 to the above equation we get:

`\begin{gathered} 4a-5+5=71+5, \\ 4a=76. \end{gathered}`

Dividing the above equation by 4 we get:

`\begin{gathered} (4a)/(4)=(76)/(4), \\ a=19. \end{gathered}`

Finally, substituting a=19 in the second and third equation we get:

`\begin{gathered} k=19-5=14, \\ j=2\cdot19=38. \end{gathered}`

Answer:

Number of orders Kala served: 14.

Number of orders Abdul served: 38.

Number of orders Joe served: 19.