Question

The cost in dollars for removing p percent of pollutants from a river in Smith County is Find the cost of removing 20%Cost for removing 20%, in dollars is = _________Find the cost of removing half of the pollutants. Cost for removing half, in dollars is = __________ Find the cost of removing all but 5% of the pollutants. Cost for removing all but 5%, in dollars, is = _________

Answer 1

Given the cost of removing p percent of pollutant from a river is Smith County in dollars as

`C(p)=(71000p)/(100-p)`

To find the cost of removing the pollutant for a particular percentage, we will substitute the value of the pollutant in the cost formula above.

Thus, for p equal to 20%

`\begin{gathered} C(20)=(71000*20)/(100-20)=(1420000)/(80) \\ C(20)=\text{ \$}17,750 \end{gathered}`

Hence, the cost of removing 20% of the pollutant is $17,750

The cost of removing half of the pollutants is equivalent to the cost of removing 50%, thus, p in percentage is 50%

`\begin{gathered} C(50)=(71000*50)/(100-50)=(3550000)/(50) \\ C(50)=\text{ \$}71,000 \end{gathered}`

Hence, the cost of removing half of the pollutants is $71,000

The cost of removing all but 5% of the pollutant is equivalent to the cost of removing 95% of the pollutants. Hence, p is 95

`\begin{gathered} C(95)=(71000*95)/(100-95)=(6745000)/(5) \\ C(95)=\text{ \$}1,349,000 \end{gathered}`

Hence, the cost of removing all but 5% of the pollutants is $1,349,000