Question

PLEASE HELP I JUST NEED TO KNOW THE POINTS AND HOW THE GRAPH LOOKS LIKE

Answer 1

You have the following function:

`g(x)=2x^2-4x-16`

the x coordinate of the vertex is given by:

`x=-(b)/(2a)`

in this case, a = 2 and b = -4. Replace these values into the previous expression and simplify:

`x=-(-4)/(2(2))=1`

next, replace the previous values of x into the function g(x):

`\begin{gathered} g(1)=2(1)^2-4(1)-16 \\ g(1)=-18 \end{gathered}`

then, the vertex is (1,-18)

In order to graph, calculate another point for any value of x, for instance, for x = 0:

g(0) = 2(0)^2 - 4(0) - 16