Question

what mass of water is need to dissolve 34.8 g of Copper (II) Sulfate in order to prepare a 0.521 m solution?

Answer 1

What mass of water is needed to dissolve 34.8 g of copper(II) sulfate in order  to prepare a 0.521 m solution?  Calculate the freezing point of a solution made from 32.7 g of propane, C3H8, dissolved in 137.0 g of benzene, C6H6. The freezing point of benzene  is 5.50° C and its Kf is 5.12° C/m.\ Calculate the concentration of nitrogen gas in a 1.00 L container exerting a  partial pressure of 572 mm Hg at room temperature. Henry’s law constant  for nitrogen at 25° C is 6.8 x 10-4 mol/L·atm.

Answer 2

419.2 g of water

Step-by-step explanation:

0.521 = 0.521 moles of CuSO4 in 1000 ml (1 kg) of water

moles = mass/molar mass

34.8 g of CuSO4 = 34.8/159.6086 moles

= 0.2180 moles

0.521 moles of CuSO4 is in 1 kg of water gives 0.521 M

Therefore, 0.2180 moles of CuSO4 in X kg of water will give 0.521 M

X = 0.218/0.52

= 0.4192 kg

= 419.2 g

Therefore, 419.2 g of water will be needed to dissolve 34.8 g of CuSO4 in order to prepare 0.521 molar solution.