Question

You have a concave mirror with a focal length of 100.0 cm, and you want an image that is upright and 10.0 times as tall as the object. Where should you place the object?Select one:a.9.09 cmb.12.09 cmc.7.12 cmd.5.8 cm

Answer 1

a. 9.09cm

Explanation:

Given:

Focal length = 100 cm

Distance image = -10 cm

We use the following formula to calculate the value of the distance of the object:

`(1)/(d_o)+(1)/(d_i)=(1)/(f)`

We substitute each value and calculate the distance of the object just like this:

`\begin{gathered} (1)/(d_o)+(1)/(-10)=(1)/(100) \\ \\ (1)/(d_(o))=(1)/(100)+(1)/(10) \\ \\ (1)/(d_o)=(11)/(100) \\ \\ d_o=(100)/(11) \\ \\ d_o=9.09\text{ cm} \end{gathered}`

Therefore, the correct answer is option a. 9.09cm