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Hey I just need someone to check my work and see what else i might need to add on. This is algebra 2

Hey I just need someone to check my work and see what else i might need to add on-example-1
User MrClean
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1 Answer

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20 votes

To answer this question we will use the following property of sets:


|A\cup B|=|A|+|B|-|A\cap B|

(a) Since Ash has 153 cards in his collection (without any duplicates), Brock has 207 cards in his collection (also without any duplicates) and they have 91 cards in common, then:


\begin{gathered} |AshCards\cup BrockCards|=|AshCards|+|BrockCards|-|AshCards\cap BrockCards| \\ =153+207-91. \end{gathered}

Simplifying the above result we get:


|AshCards\cup BrockCards|=269.

(b) Expressing the above result using set notations:


|A\cup B|=269.

Answer:

(a) There are 269 unique cards in between them.

(b)


|A\cup B|=269.
User Artanis
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