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What is the equation for a circle with center (2, -3) and radius of 6?

Question 5 options:

(x + 2)2 + (y + 3)2 = 36


(x - 2)2 + (y + 3)2 = 6


(x - 2)2 + (y + 3)2 = 36


(x - 2)2 + (y - 3)2 = 36

1 Answer

2 votes
The general formula for a circle is:
x^2 + y^2 = r^2

Since the r^2 = 36, we know the first two options are incorrect

If the circle's centre is at (2, -3), the numbers being squared should be the negative of the coordinate

So, the final answer is (x-2)^2 + (y+3)^2 = 36
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