Question

Emperical formula for 0.0200 mole of al and 0.0600 mole of cl

Answer 1

The Al to Cl ratio is
`(0.0200)/(0.060) = (1)/(3)`. Meaning that there is 1 Al to every 3 Cl, and so the empirical formula is
`AlCl_(3)`.

Answer 2

Empirical formula for the given elements =
`AlCl_3`

Step-by-step explanation:

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Moles of aluminum = 0.0200 mol

Moles of chlorine = 0.0600 mol

For empirical formula , divide the smallest number of moles from each moles of element.

Aluminium =
`(0.0200 mol)/(0.0200 mol) =1`

Calcium =
`(0.600 mol)/(0.0200 mol) =3`

Empirical formula for the given elements =
`AlCl_3`