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Which equation is correct? sec x° = opposite ÷ adjacent cot x° = opposite ÷ adjacent cosec x° = opposite ÷ adjacent sec x° = hypotenuse ÷ adjacent
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4 votes
Which equation is correct?

sec x° = opposite ÷ adjacent
cot x° = opposite ÷ adjacent
cosec x° = opposite ÷ adjacent
sec x° = hypotenuse ÷ adjacent

User Vstepaniuk
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1 Answer

4 votes
The correct equation is the last one, where secx =hypotenuse ÷ adjacent, secx is the inverse of cosx, and if you recall, cosx=adjacent÷hypotenuse
User Rodrigo Rubio
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