Multiply.4y=2y3v2.4v7

Miga asked Jan 21, 2023

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Miga asked Jan 21, 2023

by Miga

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13 votes

Let's recall one of the properties of exponents:

$x^4\ast x^5=x^{4\text{ + 5}}=x^9$

Therefore, in our exercise we have:

$4y\text{ }\ast2y^3=8y^{4\text{ }}andv^2\ast4v^7=4v^9$
$8y^4\ast4v^9=32y^4v^9$

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