Question

Write an equation perpendicular to y= 5x+2 that goes through the point (-10,-3). I am learning about how to solve systems of equations by either substitution or elimination.

Answer 1

The slope of the line
`y=5x+2` is 5. Any line perpendicular to this would have slope
`-\frac15`. Since you know a point that the perpendicular line passes through, you can use the point-slope form to find the equation of the perpendicular line.


`y-(-3)=-\frac15(x-(-10))\implies y+3=-\frac15x-2\implies y=-\frac15x-5`