Question

Calculate the force between charges of 5.0x10^-8c and 1.0x10^-7c if they are .15m apart

Answer 1

Given data:

`\begin{gathered} Q_1=5.0*10^(-8)\text{ C} \\ Q_2=1.0*10^(-7)\text{ C} \\ r=0.15\text{ m} \end{gathered}`

The electrostatic force is given as,

`F=(KQ_1Q_2)/(r^2)`

Here, K is electrostatic force constant.

Substituting all known values,

`\begin{gathered} F=\frac{9*10^9*5*10^(-8)*1*10^(-7)^{}}{(0.15)^2} \\ =2*10^(-3)\text{ N} \end{gathered}`

Therefore, the force between the charges is 2×10^(-3) N. Hence, option (d) is the correct choice.