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12 votes
12 votes
Good morning, I need help on this questions. Thanks :)

Good morning, I need help on this questions. Thanks :)-example-1
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User Vaelden
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2 Answers

21 votes
21 votes

Answer: Hl

Explanation:

User Nathanvda
by
2.4k points
18 votes
18 votes

The observed values are given in the table shown in the question. The line of best fit is given to be:


y=-1.1x+90.31

where x is the average monthly temperature and y is the heating cost.

A residual is a difference between the observed y-value (from scatter plot) and the predicted y-value (from regression equation line). The formula will be:


Residual=Observed\text{ }y\text{ }value-Predicted\text{ }y\text{ }value

QUESTION A

The average monthly temperature is 24.9:


x=24.9

Observed cost:


y=51.00

Predicted cost:


\begin{gathered} y=-1.1(24.9)+90.31=-27.39+90.31 \\ y=62.92 \end{gathered}

Residual:


\begin{gathered} R=51.00-62.92 \\ R=-11.92 \end{gathered}

QUESTION B

The average monthly temperature is 35.9:


x=35.9

Observed cost:


y=67.00

Predicted cost:


\begin{gathered} y=-1.1(35.9)+90.31=-39.49+90.31 \\ y=50.82 \end{gathered}

Residual:


\begin{gathered} R=67.00-50.82 \\ R=16.18 \end{gathered}

User Mike Fleming
by
3.0k points
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