Question

3x^2 + 19x = 154 quadratic formula

Answer 1

for ax²+bx+c=0
x=
`(-b+/- √(b^2-4ac) )/(2a)`
given

3x²+19x=154
minus 154 both sides
3x²+19x-154=0
a=3
b=19
c=-154

subsiture

x=
`(-(19)+/- √((19)^2-4(3)(-154)) )/(2(3))`
x=
`(-19+/- √(361+1848) )/(6)`
x=
`(-19+/- √(2209) )/(6)`
x=
`(-19+/- 47 )/(6)`

so
x=
`(-19+ 47 )/(6)` and x=
`(-19- 47 )/(6)`
x=
`(28)/(6)` and x=
`(-66)/(6)`
x=14/3 and -11