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9. How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°C to 50.0°C? The specific heat of water is 4.184 J/(g•°C).
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9. How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°C to 50.0°C? The specific heat of water is 4.184 J/(g•°C).

User Glenn Utter
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Heat = mass * specific heat * change in temperature

Heat = 15.5 * 4.184 * (50 - 20)

Heat = 15.5 * 4.184 * 30 ==== 1946J
User Taron Saribekyan
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