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Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls. In how many ways can the selection be made so that at least one of each color is draw?
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Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls.

In how many ways can the selection be made so that at least one of each color is draw?

User Yogesh Aggarwal
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2 Answers

4 votes
16? I'm not too good with probability but my guess is that there are two possible positions for each marble and 4 marbles so 1/2*1/2*1/2*1/2 would be 1/16 meaning 16 possible outcomes but I has to have one of each at least so 14
User Jocko
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8.3k points
4 votes
that is confusing :/
User Vemula Abilash
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8.7k points
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