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7. What is the velocity of a 850kg car after starting at rest when 13,000J of work is done to it.

User DorkRawk
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1 Answer

26 votes
26 votes

Answer:

5.53 m/s

Step-by-step explanation:

The work is equal to the change in the kinetic energy, so


\begin{gathered} W=\Delta KE \\ W=(1)/(2)m(v^2_f-v^2_i)^{}^{} \end{gathered}

Since the car starts at rest, the initial velocity vi = 0 m/s, so we can solve for the final velocity vf as follows


\begin{gathered} W=(1)/(2)mv^2_f \\ 2W=mv^2_f \\ (2W)/(m)=v^2_f \\ v_f=\sqrt[]{(2W)/(m)} \end{gathered}

So, replacing the work W = 13,000J and the mass m = 850kg, we get:


\begin{gathered} v_f=\sqrt[]{\frac{2(13,000J)}{850\operatorname{kg}}} \\ v_f=5.53\text{ m/s} \end{gathered}

Therefore, the velocity is 5.53 m/s

User Gileri
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