383,773 views
18 votes
18 votes
The function f(t) = 2(2.25)^t models the growth of bacteria cells, where f(t) is the number of bacteria cells and t is time in days. After 10 days, approximately how many bacteria cells are there?

User Peter Friese
by
3.0k points

1 Answer

17 votes
17 votes

Step 1

write out the function


\begin{gathered} f(t)=2(2.25)^t \\ \end{gathered}

Step 2

for every input, an input produce unique output

t = 10days is the input

Step 3

substitute t = 10 in the function


\begin{gathered} f(t)=2(2.25)^(10) \\ =\text{ 2 }*2.25^(10) \\ =\text{ 2 x 3325.25673} \\ =\text{ 6650.51} \\ =\text{ 6651} \end{gathered}

User BobBrez
by
2.4k points