Question

In 2011, an earthquake in Chile measured 8.3 on the Richter scale. How many times more intense was thisearthquake then than the 2011 earthquake in Papa, New Guinea that measured 7.1 on the Richter scale? Roundthe answer to the nearest integer.

Answer 1

Step 1:

In this question, we are given that:

In 2011, an earthquake in Chile measured 8.3 on the Richter scale. How many times more intense was this earthquake then than the 2011 earthquake in Papa, New Guinea that measured 7.1 on the Richter scale?

Round the answer to the nearest integer.

Step 2:

From the question, we are to use this formula:

Now, we have that:

`\begin{gathered} M_2-M_1=\log ((I_2)/(I_1)) \\ \text{where M}_2=\text{ 8.3} \\ \text{and} \\ M_1=\text{ 7. 1} \end{gathered}`

Hence, we have that:

`\begin{gathered} \text{8. 3 - 7. 1 = log ( }(I_2)/(I_1)) \\ 1.2=log_(10)\text{ (}(I_2)/(I_1)) \\ ((I_2)/(I_1))\text{ = }10^(1.2) \end{gathered}`

CONCLUSION:

The final answer is:

`((I_2)/(I_1))=10^{1.\text{ 2}}`