Question

A 10.0 Molar solution is used to make 100. mL a 5.00 Molar solution. How much of the original solution is used?

A. 10.0 mL
B. 50.0 mL
C. 500. mL
D. 100.0 mL

Answer 1

Data:

`M_(concentrated) = 10\:mol`

`V_(concentrated) = ?`

`M_(dilute) = 5\:mol`

`V_(dilute) = 100\:mL`

Formula: Dilution Calculations


`M_(concentrated) * V_(concentrated) = M_(dilute) * V_(dilute)`

Solving:



`M_(concentrated) * V_(concentrated) = M_(dilute) * V_(dilute)`

`10 * V_(concentrated) = 5 * 100`

`10V_(concentrated) = 500`

`V_(concentrated) = (500)/(10)`

`\boxed{\boxed{V_(concentrated) = 50\:mL}} \end{array}}\qquad\quad\checkmark`

Answer:
B. 50.0 mL