a 4.0 kg ball is attached to 0.70 m string and spun at 2.0 m/s. what is the centripetal acceleration ?

asked Dec 9, 2018 32.4k views

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2 votes

a(cp) = v^2/R

a(cp) = (2.0)^2/0.70

a(cp) = 4.00/0.70

a(cp) = 5.7 m/s^2 (approximately)

Simon Duff answered Dec 11, 2018

8.3k points

2 votes

Hope this helps, have a great day ahead!

Bhavesh G answered Dec 16, 2018

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