Question

What is the mass (in grams) of 9.27x1024 molecules of methanol(CH3OH)

Answer 1

Moles of methanol = 9.27x10^24/6.02x10^23 = 15.398 moles.

Mass of methanol = moles of methanol x molar mass of methanol
= 15.398 x 32.042
= 493.38 grams.

Hope this helps!

Answer 2

Answer: 493 grams

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadro's number}}=(9.27* 10^(24))/(6.023* 10^(23))=15.4moles`

1 mole of
`CH_3OH` weighs = 32 g

15.4 moles of
`CH_3OH` weigh =
`(32)/(1)* 15.4=493g`

Thus mass of
`9.27* 10^(24)` molecules of methanol weigh 493 grams.