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If the circumference of the circular base of a cylinder is doubled, how does the volume of the cylinder change?

Question 16 options:

The volume is quadrupled.


The volume is tripled.


The volume is eight times larger.


The volume is doubled.

User Arocks
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2 Answers

5 votes
V=hpir^2

C=2pir
when it is doubled
newC=2pi(2r)
that means radius is doubled

sub 2r for r in volume

V=hpi(2r)^2
v=hpi4r^2
v=4(hpir^2)
it is quadrupled


answer is 1st option

User Shamseer Ahammed
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3 votes

Answer:

The volume is quadrupled

Explanation:

we know that

The volume of the cylinder is equal to


V=\pi r^(2) h

In this problem

If the circumference of the circular base is doubled then , the radius is doubled too, because the circumference and the radius represent a linear direct variation

therefore

The new volume is equal to


V=\pi (2r)^(2) h


V=4\pi r^(2) h

The new volume is four times the original volume

User Nishchay Sharma
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7.7k points