Question

In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO → 5N2 + 6H2O The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

a- 23.7 grams

b- 10.5 grams

c- 73.5 grams

d- 32.7 grams

Answer 1

the anwser is b10.5g

Answer 2

4NH₃ + 6NO → 5N₂ + 6H₂O

mol of NO =
`(mass of NO)/(Molar Mass of NO)`

=
`(27.8 g)/(30.01 g / mol)`

= 0.93 mol

Based on the balance equation mole ratio of NH₃ : NO is 4 : 6
= 2 : 3

If mol of NO = 0.93 mol

then mol of NH₃ =
`(0.93 mol * 2)/(3)`

= 0.62 mol

Mass of ammonia = mol × molar mass

= 0.62 mol × 17.03 g/mol

= 10.54 g

Therefore B is the best answer