Question

11. The length of a rectangle is 2 more than the width. The perimeter is 32. Find the

length and width.

Answer 1

length = 9, width = 7

Explanation:

length = l, also w+2 width = w

perimeter = 2w + 2l

create an equation: 32 = 2(w) + 2(w+2)

simplify

32 = 2w+2w+4

32 = 4w+4

28=4w

w=7

solve for length

l = w+2

l=7+2

l=9