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(x+y=3
(3x+2y=14
what is the coordinates for this problem

User Botto
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1 Answer

2 votes


3x - 2y + 2y > -14 + 2y

3x + 0 > -14 + 2y

3x > -14 + 2y

3x + 14 > -14 + 14 + 2y

3x + 14 > 0 + 2y

3x + 14 > 2y

(3x + 14)/2 > 2y/2

(3x + 14)/2 > y*(2/2)

(3x + 14)/2 > y*(1)

(3x + 14)/2 > y

y < (3x + 14)/2

y < 3x/2 + 14/2

y < 3x/2 + 7

y < (3/2)*x + 7

“y” is LESS THAN (3/2)*x + 7

the slope intercept form of the inequality is: y < (3/2)*x + 7


STEP 2: Temporarily change the inequality into an equation by replacing the < symbol with an = symbol.

y < (3/2)*x + 7

y = (3/2)*x + 7


STEP 3: Prepare the x-y table using the equation from Step 2.

Using the slope intercept form of the equation from Step 2, choose a value for x, and then compute y for at least three points.

Although you could plot the graph with just two sets of x-y coordinates, you should compute at least three different sets of coordinates points to ensure you have not made a mistake. All three x-y coordinates must lie on the same straight line. If they do not, you have made a mistake.

You can choose any value for x.


For example, (arbitrarily) choose x = -2

If x = -2,

y = (3/2)*x + 7

y = (3/2)*(-2) + 7

y = 4
User Mike Ellis
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7.8k points