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Find the area of a sector with a central angle of 133 degrees and a radius of 13.9 millimeters. Round to the nearest tenth.

A. 224.2 mm^2
B. 448.5 mm^2
C. 64.5 mm^2
D. 16.1 mm^2

2 Answers

1 vote
The answer is A.
First, you change the degrees to radians.

133(pi/180)= 2.3212879051524583373085087220899 (long number)

Then you just plug that into the formula!

(r^2*theta)/2

(13.9^2 * 2.3212879051524583373085087220899) / 2 = 224.24801807725323767568848509749
User Augray
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6.3k points
2 votes

Answer:

Area of sector = 224.2 mm².

Explanation:

Given : a central angle of 133 degrees and a radius of 13.9 millimeters.

To find : Find the area of a sector.

Solution : We have given that

central angle = 133 degrees

Radius = 13.9 millimeter.

Area of sector =
(theta)/(360) * \pi * radius^(2).

Plugging the values

Area of sector =
(133)/(360) * 3.14 * (13.9)^(2).

Area of sector =
(133)/(360) * 3.14 * 193.21.

Area of sector =
(133)/(360) * 606.6794.

Area of sector =
(80688.3602)/(360).

Area of sector = 224.134333889 mm²

Area of sector = 224.2 mm² ( nearest tenth)

Therefore, Area of sector = 224.2 mm².

User DrWeeny
by
6.9k points