335,149 views
43 votes
43 votes
A plate of cookies and mug of milk are pushed across a smooth table with the same force. The mass of the plate of cookies is 222 times the mass of the mug of milk. Assume that friction is negligible.

How do the objects' accelerations compare?

User Sarthak Mishra
by
2.4k points

2 Answers

18 votes
18 votes

Answer:

Step-by-step explanation:

Given:

m₁ = m - Mass of milk mug

m₂ = 222·m₁ = 222·m - Mass of a plate of biscuits

F₁ = F₂ = F

________________

a₂ / a₁ - ?

2 Newton's law:

a = F / m

a₁ = F / m₁ = F / m

a₂ = F / m₂ = F / (222·m)

a₁ / a₂ = (F·222·m) / (F·m) = 222

The acceleration of a mug of milk is 222 times the acceleration of a bowl of cookies

User Cboettig
by
2.8k points
14 votes
14 votes

Answer:The two objects have different amounts of acceleration due to the mass of the two objects being different

Explanation: The mass will affect acceleration. The higher the mass, the slower the acceleration. The formula for acceleration is a = f/m or acceleration = force divided by mass. The acceleration is faster for the milk glass and slower for the plate with cookies because the plate with cookies has a higher mass than the glass of milk.

User Ardin
by
2.3k points