1 Answer

Janks · Answer 1 · 2018-09-12T09:00:01+0000

Answer: The value of the determinant is 1.

Step-by-step explanation: The given system of linear equation is as follows:

$6x+y=4~~~~~~~~~~~~~~~~(i)\\\\5x-y-7=0\\\\\Rightarrow 5x-y=7~~~~~~~~~~~(ii)$

The first column of the determinant gives the coefficients of 'x' and the second column gives the coefficients of y in the two equations.

Therefore, the determinant for the given system is

$D=\begin{vmatrix} 6& 1\\  5& 1\end{vmatrix}=6* 1-5* 1=6-5=1.$

Thus, the required value of the determinant is 1.

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