using the decay law formula N=No x e^-kt
at t=0, No=5 million barrels
at t= 6years, N= 2,500,000 barrels=No/2
a) the rate is 5 millions - 3,000,000=2,000,000 barrels
b) let t this time
so N=No x e^-kt, implies 250,000=5,000,000,x e^-kt
25=500,x e^-kt, 5=100,x e^-kt, we must search for k,
at t=0, No=5 million barrels
at t= 6years, N= 2,500,000 barrels=No/2
so N=No/2=No x e^-kt implies 1/2=e^-6k, so ln(1/2)= lne^ -6k, implies so
-0.69= -6k and k= 0.11
finally we can use N=No x e^-0.11t
250,000= 5,000,000 x e^-0.11t
1= 20 x e^-0.11t and 1/20= e^-011t, 0.05=e^-0.11t, ln(0.05)= - 0.11t
-3= -0.11t, so t = 27.22 years