Answer:
The lengths of AB and EF are 10 and 2 respectively
Explanation:
The lengths of AB and EF are 10 and 2 respectively
If the triangle ABC and DEF are similar, based on the similarity theorem of a triangle;
AB/DE = BC/EF
5x/4 = 5/x
5x² = 20
x² = 20/5
x² = 4
x = 2
Since the value of x is 2, length of AB is 5x = 5(2) = 10
Since EF = x, hence EF = 2
The lengths of AB and EF are 10 and 2 respectively