88.3k views
1 vote
For a movie stunt, an empty truck with a mass of 2000 kg goes 10 m/s and runs into a stopped car of mass 1000 kg. the truck then keeps moving and pushes the car along with it. if there are no other forces acting on this system, describe the results of the collision?

User KQS
by
7.3k points

2 Answers

4 votes

Step-by-step explanation:

Given that,

Mass of the truck, m₁ = 2000 kg

Mass of the stopped car, m₂ = 1000 kg

Initial speed of the truck, u₁ = 10 m/s

Initial speed of the car, u₂ = 0 (at rest)

As there is no other forces acting on this system, the momentum remains constant. Let v is the combined speed of the system after the collision. So,


m_1u_1+m_2u_2=(m_1+m_2)v


2000* 10+1000* 0=(1000+2000)v

v = 6.667 m/s

Therefore, the speed of the combined mass is 6.667 m/s and the speed of the combined mass is less than initial speed.

User HitLikeAHammer
by
7.1k points
2 votes

ANSWER

Both trucks will move together with speed v = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

EXPLANATION

As we know that there is no external force on the system of two trucks

So here momentum of the two trucks before collision and after collision will remain same

So here we will have


m_1v_(1i) + m_2v_(2i) = m_1v_(1f) + m_2v_(2f)

so here we will have


v_(1i) = 10 m/s


v_(2i) = 0


m_1 = 2000 kg


m_2 = 1000 kg

now we will have


2000* 10 + 1000* 0 = (2000 + 1000) v


v = (20000)/(3000) = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

User Mussdroid
by
6.7k points